2u^(-3/2)=1/5

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Solution for 2u^(-3/2)=1/5 equation: 


D( u )

u < 0

u = 0

u < 0

u = 0

u = 0

u in (0:+oo)

2*u^(-3/2) = 1/5 // - 1/5

2*u^(-3/2)-(1/5) = 0

2*u^(-3/2)-1/5 = 0

2*u^(-3/2) = 1/5 // : 2

u^(-3/2) = 1/10

-3/2 < 0

1/(u^(3/2)) = 1/10 // * u^(3/2)

1 = 1/10*u^(3/2) // : 1/10

10 = u^(3/2)

u^(3/2) = 10 // ^ 2

u^3 = 100 // ^ 1/3

u = 100^(1/3)

u = 100^(1/3)

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